How to drop an index which has a constraint on the table?
while droping the index on the table wheather i should remove the
constraint or disable the constraint or without droping the
constraint
I use Oracle 10.0.2.0.1.If I create a table with constraint key; after that I create an unique index key, I got an error. Does it mean when I create a table with constraint the unique index are automatically created and I could not create index key as I did as below?
create table test_const(ename varchar2(50) not null,
key_num number not null,
descr varchar2(100),
constraint constraint_test_const unique (ename, key_num));
create unique index test_const_idx on test_const
(
"ENAME","KEY_NUM"
)
tablespace tmp_data;
Error report: SQL Error: ORA-01408: such column list already indexed 01408. 00000 - "such column list already indexed" added [pre] tags by Sriram
I ran into an issue in a project where a function is recreating an index-organized table by doing:Table Structure:
CREATE TABLE table_iot(
...)
ORGANIZATION INDEX
OVERFLOW ...;
Recreate Steps:
1) Populate global temporary staging table (gtt) with data
-- where gtt is staging for target index-organized table (iot)
2) Lock the target index-organized table (iot)
3) Copy old iot data to gtt
-- gtt now contains old and new data
4) Create new index-organized table (iot2) from gtt
-- iot2 now contains old and new data
[code]...
Because index-organized tables are primarily stored in a B-tree index, you can encounter fragmentation as a consequence of incremental updates. However, you can use the ALTER TABLE...MOVE statement to rebuild the index and reduce this fragmentation.The following statement rebuilds the index-organized table admin_docindex:
ALTER TABLE admin_docindex MOVE;
How to find out who has dropped and when was the index created in database?
View 39 Replies View Relatedi tried creating an context index. But it is aborted in the middle. do to reuse the spce i want to drop the index. But it shows an error that " cannot drop index marked as process" how to delete the index.
View 1 Replies View RelatedOn a SAP system, am trying to drop six indexes, largest is 300MB and smallest is 50MB.
I tried running drop index sapusername.index_name on the 50MB index via SQL*Plus and it seems to be taking forever. anything I can check on the database on why it is taking such a long time?
I can leave it to run overnight but worried that when I come back the next day, it will still be hanged. Is there any quick way of dropping the index, .i.e. drop immediate ...
Am not using SAP's BRTOOLs as it is also hanging from there and the SAP-ADMIN had approved for the DBA to drop it from our end instead.
db 10.2.0.4
AIX 5.2
I am trying to drop a index tablespace I moved all indexes to new tablespace there is no indexes in that tablespace even any objects but still it is not dropping.it is giving error as below.
SQL> drop tablespace ret_index including contents;
drop tablespace ret_index including contents
*
ERROR at line 1:
ORA-00604: error occurred at recursive SQL level 1
ORA-02429: cannot drop index used for enforcement of unique/primary key
SQL> alter tablespace ret_index drop datafile '/path/index3.dbf';
alter tablespace ret_index drop datafile '/path/ret_index3.dbf'
*
ERROR at line 1:
ORA-03262: the file is non-empty
try to resize
SQL> alter database datafile 4 resize 100m;
alter database datafile 4 resize 100m
*
ERROR at line 1:
ORA-03297: file contains used data beyond requested RESIZE value
Tablespace size is 280gb
i want to get table name, constraint name, constraint type with join processes in string type. this is what i want: alter table tablename add constraint constraintname constrainttype(columnname)
View 1 Replies View RelatedLet's consider such table that all rows fit into single block:
SQL> create table test as select rownum id, '$'||rownum name from dual connect by level <= 530;
Table created.
SQL> create index i_test on test(id);
Index created.
SQL>
SQL> begin
[code].....
why does approach with full scan take longer even if table occupies only one data block? PS. 11gR2
I have a huge table (about 60 gb) partition over range. The index on this table is global index created on 4 columns together. I have a query which is running very slowly. The explain plan is showing the use of this global index.Explain plan is not showing pstart and pend because the index is global.
View 6 Replies View Relatedprimary key constraint on transaction_dtl_bk is affecting the insertion of next correct rows.
CREATE OR REPLACE PROCEDURE NP_DB.san_po_nt_wnpg_1 (
dt DATE
)
IS
v_sql_error VARCHAR2 (100); -- added by sanjiv
v_sqlcode VARCHAR2 (100); ---- added by sanjiv added by sanjiv
[code]...
How to force an index if the table not using the index?
View 10 Replies View RelatedI have a table that has 2 columns of type nested table. Now in the purge process, when I try to truncate or drop a partition from this table, I get error that I can't do this (because table has nested tables). how I will be able to truncate/drop partition from this table? IF I change column types from nested table to varray type, will it work?
Also, is there any short method of moving existing data from a nested table column to a varray column (having same fields as nested table)?
how to i insert a constraint of words into the table example below.I am new to this stuff man.
Create table Orders
(
orderID Number(8) Primary Key,
orderDate Date Not Null,
methPmt Varchar2(10),
custID Number(5),
orderSource Number(2),
Foreign Key(custID) Reference Customer(custID),
Foreign Key(ordersource) Reference OrderSource(ordersource)
);
The catch is I am required to enter a constraint of the methPmt will only take values of "CASH", "CREDIT" or "CHEQUE" only.
How am I suppose to enter this constraint value into the creation of this table?
I want to know constraint name of a particular table if it exists.Here are the queries that i tried to find the constraint name of a particular table but the results were 'no rows selected'.
Queries:
select constraint_name from user_cons_columns where table_name='x';
select constraint_name from user_constraints where table_name='x';
I'm trying to create a new table which has a date field (date of birth) and I want to include a constraint which will not allow me to add values if they are over 21 years old. I'm using SQLPlus .
View 3 Replies View RelatedI would like to add a constraint "default value" for a table column, with a name.
I know how to do it for a constraint "not null" : ALTER TABLE tablename MODIFY columnname CONSTRAINT constraintname NOT NULL;
But I don't know how to do it for a constraint "default value".How can I do ?
Can we modifying the existing constraint on table?I have table level UNIQUE constraint on 3 columns of table.I need to modify the UNIQUE constraint to 2 columns? Instead of dropping/recreating the constraint, is there any option to modify the existing constraint
Ex
CREATE TABLE TEST_CONST(NUM1 NUMBER , NUM2 NUMBER , NUM3 NUMBER , UNIQUE (NUM1 ,NUM2,NUM3)); ;
SELECT * FROM USER_CONS_COLUMNS UCC WHERE UCC.TABLE_NAME LIKE 'TEST_CONST';
ALTER TABLE TEST_CONST MODIFY CONSTRAINT SYS_C0025132 UNIQUE(NUM1,NUM2);
ORA-00933: SQL command not properly ended
Third statement is not executing fine .
i have one table HR.employees
SQL> desc hr.employees
Name Null? Type
----------------------------------------- -------- ----------------------------
EMPLOYEE_ID NOT NULL NUMBER(6)
FIRST_NAME VARCHAR2(20)
LAST_NAME NOT NULL VARCHAR2(25)
EMAIL NOT NULL VARCHAR2(25)
PHONE_NUMBER VARCHAR2(20)
HIRE_DATE NOT NULL DATE
JOB_ID NOT NULL VARCHAR2(10)
SALARY NUMBER(8,2)
COMMISSION_PCT NUMBER(2,2)
MANAGER_ID NUMBER(6)
DEPARTMENT_ID NUMBER(4)
SQL>
in this table i want to temporary disable all constraint in this employees table
There was one constraint define on the column of table that the value of column should be in range of 100 to 200. Some one has deleted the constraint. Is it possible to get the exact name of constraint from any system table.
View 7 Replies View RelatedI have a table as below. This table is not partitioned.
create table t1
(
d1 date,
n1 number not null
);
[Code]....
I took an export dump of the above table and after that I renamed the table t1 to t1_old. Then I recreated the table as below with a default constraint on d1 field.
create table t1
(
d1 date default to_date('01/01/1100','DD/MM/YYYY','NLS_CALENDAR=GREGORIAN'),
n1 number not null
[Code]....
But the problem here is the data import is taking too much time than what I expected. I can't afford a maxvalue partition here as of my DBA team mentioned if you add maxvalue partition adding partition later in a stage is difficult on this table
apply in this scenario and make the import faster. I am using oracle 10.2.0.1.0 version.
I am a junior DBA. I want to check how many columns are under PRIMARY KEY constraint.
I used dba_constraints view. Please find below details.
SQL> select OWNER,CONSTRAINT_NAME,CONSTRAINT_TYPE,TABLE_NAME from dba_constraints
2 where TABLE_NAME='DSET_PRODUCT_S';
OWNER CONSTRAINT_NAME C TABLE_NAME
------------------------------ ------------------------------ - ----------------------------------------
SCOTT SYS_C10202456 C EMPLOYEE
SCOTT SYS_C234576 C DEPT
When drop a table what happen to view,sequence,synonyms,index,constraint for the table
View 9 Replies View RelatedI have created a table below, my TL asked me to create a local unique constraint for the below table.
I went through all sites and could not find the correct solution, how to create LOCAL UNIQUE CONSTRAINT ON SUB PARTITION TABLE and LOCAL UNIQUE INDEX ON PARTITION TABLE. Creating Local Unique constraint should take care of creating local unique index creation.
Unique key columns are DET,GDS,ARRIVE_DT
CREATE TABLE SUB_PAR_TAB
(
ID VARCHAR2(100) NOT NULL,
REGION VARCHAR2(40) NOT NULL,
SOURCE VARCHAR2(80) NOT NULL,
DET VARCHAR2(80) NOT NULL,
GDS VARCHAR2(40) NOT NULL,
ARRIVE_DTDATE,
SYS_SOURCE VARCHAR2(25) ,
[code]........
Why can't we create null constraint on table level?
View 20 Replies View RelatedI used
SELECT USER_CONS_COLUMNS.CONSTRAINT_NAME,
COLUMN_NAME,
CONSTRAINT_TYPE,
[Code]...
to create a parent key table sort of thing, but for some reason there are rows that display multiple times
CONSTRAINT_NAME COLUMN_NAME CONSTRAINT_TYPE R_CONSTRAINT_NAME DELETE_RU
-------------------- -------------------- --------------- ------------------------------ ---------
SYS_C00135225 PATIENT_STATUS C
SYS_C00135226 BALANCE C
SYS_C00135227 PATIENT_STATUS C
PK_PATIENT PATIENT_NUMBER C
[Code] ..........
is it something to do with the join command
I am trying to create snapshot using the following script but I am getting the error
ERROR at line 22:ORA-12014: table 'CDA_FUNCTION' does not contain a primary key constraint
SQL> CREATE SNAPSHOT MEDA.cda_function
PCTFREE 10
PCTUSED 40
MAXTRANS 255
TABLESPACE users
STORAGE (
INITIAL 40960
[code]....
I check in dba_constraint data dictionary table for the constraints in the table CDA_FUNCTION.it is showing as follows
owner constraint_name constraint_type table_name search_condition status deferrable deferred validated generated
WEDA SYS_C0032310 C CDA_FUNCTION (LONG) ENABLED NOT DEFERRABLE IMMEDIATE VALIDATED GENERATED NAME
WEDA SYS_
i'm new to oracle environment.how can i specify NONCLUSTERD INDEX on Primary cloumn during table creation.By default it will create clusterd index but i need non-clusterd index on it.
I'm using following stmt to create normal primary constarint during table creation,
CONSTRAINT PKFORM_PROPS PRIMARY KEY (FORM_PROPS_PK) USING INDEX TABLESPACE DB123_INDEX
how can i change the above query, so that it should create NONCLUSTERED INDEX on Primary key column.
There two users a and b,and the table b.test_part.And one procedure under a ,text like below:
create or replace procedure a.sp_test
is
vs_sqls varchar2(32767);
begin
vs_sqls:='alter table b.test_part truncate partition p_day';
execute immediate vs_sqls;
end;
now,i have to grant drop any table to a.but in fact,i prefer to drop the special one table "b.test_partany" rather than any other table.how ? no by trigger!
I am trying to Truncate the table but it doesnt get truncated. When I issue the command it even doesnt throw the error. I also tried to drop the table but cant even able to drop the table. I thought table might be locked. But it allows me delete a row from the table.
I am using Oracle 11g Release 11.1.0.7.0