create or replace
Procedure ReadingsPurge
As
v_sql varchar2(500);
v_date date;
p_count NUMBER;
[Code]...
-- Code below drops partitions that are older than the NoOfDays Parameter
OPEN c1;
LOOP
FETCH c1 INTO v_partition_name, v_high_value;
EXIT WHEN c1%NOTFOUND;
[Code]....
Above code is compiling successfully.
After I added the lines makred in the red font, when I tried to execute the stored procedure, I got an error
Error starting at line 1 in command:
execute ReadingsPurge
Error report:
ORA-00933: SQL command not properly ended
ORA-06512: at "CDC_USER.READINGSPURGE", line 30
ORA-06512: at line 1
00933. 00000 - "SQL command not properly ended"
*Cause:
*Action:
I think that performance better partition table than non-partition table. How to assure partition table is better than non-partition table at SELECT operation?
I have compare a specific query EXPLAIN PLAN at partition table and non-partition table. both tables data is same. Is it true way or not?
I have a table that partitioned into six partitions. each partitions placed in different table space and every two table space placed it on a different hardisk
when I will do query select with the non-partition keys condition, how the search process ? whether the sequence (scan sequentially from partition 1 to partition 6) or partition in a hardisk is accessed at the same time with other partition in other hardisk. ( in the image, partition 1,4 accessed at the same time with partition 2,5 and 3,6)
Can i alter the table to create partition on non partition table, i have tried and could not create it. Do we have some other means to do it as this is the live table and cannot drop them else will lose the data.
Can I add range sub partition to a hash partition table. Example like this.
CREATE TABLE test ( test_id VARCHAR2(10 ) , test_TYPE VARCHAR2(5) , CREATE_DATE date ) partition by hash (test_id, test_type) Partitions 3 SUBPARTITION BY RANGE (CREATE_DATE);
When Tried, I am getting syntax error as invalid option.
When I am trying to insert record from tbl_mittal into tbl_temp table. I am facing "ORA-14400: inserted partition key does not map to any partition" error
SQL> insert into tbl_temp select * from tbl_mittal; insert into tbl_temp select * from tbl_mittal * ERROR at line 1: ORA-14400: inserted partition key does not map to any partition
AS tbl_mittal is having hugh number of records so I am providing only few rows from tbl_mittal table as test data.
Consider tables A,B,C,D,E,F. all are having 100000++ records Tables B,C,D are dependent on table A (with foreign key constraint). When I am deleting records from all tables, table B,C,D are taking max 30-40 seconds while table A is taking 30-40 mins. All tables are having indexes.
Method I have used:
1. Created Temp table
2. then deleted all records from B,C,D,E,F for all records in temp table for limit of 500.
delete from B where exists (select 1 from temp where b.col1=temp.col1);
3. why it is taking too much time for deleting records in table A.
I'm testing a procedure which loads data into my database, and after each test I want to empty some of the tables and reset the sequences. I have this script to do that...
DELETE FROM COM_MERGE; COMMIT; DELETE FROM COM_TITLE; COMMIT; DELETE FROM COM_ISSUE; COMMIT; DELETE FROM COM_PAGE_ELEMENT; COMMIT; DELETE FROM COM_ELEMENT; COMMIT; DELETE FROM COM_STORY_TITLE; COMMIT; BEGIN COM_RESET_SEQUENCES; END;
Today I added the call to the sequences procedure to my script, but I have been using the script to delete from tables for a number of days without problem.However today I am finding that when I run the script it works ok the first couple of times, but when I try running it for a third time, it hangs after the second delete (in other words it stops when it gets to the delete from COM_ISSUE). After this happened the first couple of times I stopped the db and restarted it, then the script was ok twice, but again I'm finding that the script hangs. There is no error message, but the script fails to complete.
I didn't know if it was because originally I had one commit at the end of the script, so I added commits after each delete but that didn't solve it.I am using SQL Developer but I have found the same problem when running the script from SQL Plus.This is the definition of the COM_ISSUE table (just in case the table is the source of the problem).There is only one row in COM_ISSUE.
CREATE TABLE "BILL"."COM_ISSUE" ( "CI_ID" NUMBER NOT NULL ENABLE, "CI_TITLE" NUMBER NOT NULL ENABLE, "CI_DATE" NUMBER NOT NULL ENABLE, "CI_PRICE" NUMBER NOT NULL ENABLE, "CI_PUBLISHER" NUMBER NOT NULL ENABLE, CONSTRAINT "COM_ISSUE_PK" PRIMARY KEY ("CI_ID") USING INDEX PCTFREE 10 INITRANS 2 MAXTRANS 255 COMPUTE STATISTICS STORAGE(INITIAL 65536 [code]....
How can I delete the duplicate combination of records from the below table.
CREATE TABLE test ( gidNUMBER(10), pidNUMBER(10) ); INSERT INTO test VALUES (10,20); INSERT INTO test VALUES (20,10); INSERT INTO test VALUES (25,46);
[code]....
The condition is if GID = PID and PID = GID then only one combination of these records should be retained. For example Out of 10-20 and 20-10 only one record should be retained.
Consider tables A,B,C,D,E,F. all are having 100000++ records Tables B,C,D are dependent on table A (with foreign key constraint). When I am deleting records from all tables, table B,C,D are taking max 30-40 seconds while table A is taking 30-40 mins. All tables are having indexes.
Method I have used:
1. Created Temp table
2. then deleted all records from B,C,D,E,F for all records in temp table for limit of 500. delete from B where exists (select 1 from temp where b.col1=temp.col1);
3. Why it is taking too much time for deleting records in table A.
Is there any thing that during deleting data from such master table, it is referring to all dependent tables even if dependent data is not present ?
How to find the size pf a partition in a partition table?I guess we need to query views like dba_tab_partitions but I am not very sure. will running dbms_stats.gather_table_stats('schema_name,'table_name,'partition_name')
I think that performance better partition table than non-partition table. How to assure partition table is better than non-partition table at SELECT operation?
I have compare a specific query EXPLAIN PLAN at partition table and non-partition table. both tables data is same. Is it true way or not?
I am trying to add partition to table without partition
with following code
ALTER TABLE ACC_LOC1_TAB ADD PARTITION testpart BY RANGE (ALT_AUTHDT) (PARTITION UPTO_2010 values less than (31-mar-2010), PARTITION APR_JUN_10 VALUES less than (30-JUN-2010), PARTITION JUL_SEP_10 VALUES less than (30-SEP-2010), PARTITION OCT_DEC_10 VALUES less than (31-DEC-2010), PARTITION JAN_MAR_11 VALUES less than (31-MAR-2011))
I am using Oracle 11.2.0.1 Oracle Database.I have a table with 10 Million records and it's a Non Partitioned Table.
1) I would like to partition the table (with partition by range ) without creating new table . I should do it in the existing table itself (not sure DBMS_ REDEFINITION is the only option ) (or) can i use alter table ...?
2) Add one partition which will have data for the unspecified range.
i have table with range partition and list sub-partition..can i add one more list sub-partition if it is not possible , i have to drop first sub-partition.
how to partition and index my table for a special problem.
The table:
CREATE TABLE TEST ( ID NUMBER PRIMARY KEY, U_VALUE NUMBER NOT NULL, -- Ranges from 0 - 30.000.000 O_VALUE NUMBER NOT NULL, -- Ranges from U_VALUE - 30.000.000 CREATE_TS TIMESTAMP DEFAULT SYSTIMESTAMP NOT NULL, UPDATE_TS TIMESTAMP NOT NULL, ITEM_TYPE NUMBER NOT NULL --<< Only 4 different values >> );
As you can see, U_VALUE is ALWAYS lower than O_VALUE.I need to have the CREATE_TS in either main- or subpartition do drop the partitions after some time so i don,t have to use DELETE statements. The table has 360 millions rows.
The application has only 8 query which will always use a WHERE clause like this:
SELECT * FROM TEST WHERE U_VALUE <= :1 AND O_VALUE => :2 AND ITEM_TYPE = :3
1. Is there any good technique how to create a good index for the queries (application will execute 120 queries per second)?
All partitions were dropped, but three; these three returned the same error when trying to drop them:
SQL> alter table dw.F_TFP_CP_MONTH drop partition P_201112; alter table dw.F_TFP_CP_MONTH drop partition P_201112 * ERROR at line 1: ORA-01426: numeric overflow
SQL> alter table dw.F_TFP_CP_MONTH drop partition P_201111; alter table dw.F_TFP_CP_MONTH drop partition P_201111 * ERROR at line 1: ORA-01426: numeric overflow
SQL> alter table dw.F_TFP_CP_MONTH drop partition P_201110; alter table dw.F_TFP_CP_MONTH drop partition P_201110 * ERROR at line 1: ORA-01426: numeric overflow
So, the situation now is that the table only has these three partitions, and we are not able to empty the table, so that we can later purge it and recover the
space.
free that space and empty the contents of the table?
i want to ask about indexing in partition table. i have table that indexed by local index. when i want to select all data. I execute this query
select * from Book_Issue_Part where status='Pinjam';
but it does not select all data, only partly data have selected. is it a wrong query to select all data in indexing partition table? so what query should i execute to get all data.
We have a transaction table and has 30 million rows. The table is not partitioned till date. We need to create partition on this table. We had an idea of moving this data to a temporary table and create partition[range]on the original table and move the data back.
I am facing a problem in fetching / updating records from a customer details table having around 20 million records. The table contains around 30 fields with 'MOBILE_NO' as primary key. most of the queries are having 'mobile_no' in where clause .I am planning to hash partition that table using mobile_no column as there is no other column available which can be used for partition.
clarify whether creating hash partition on such key would increase performance of data extraction as I have read on net that hash partitioning is not effective for performance tuning.
CREATE TABLE table_partition(sales number,year date,item char(4)) partition by range(year) ( PARTITION p1 VALUES LESS THAN 1980, PARTITION p2 VALUES LESS THAN 1982, PARTITION p3 VALUES LESS THAN 1985 );
The above code will create table with partition.
That is the table is not existed before we are creating table with partition.
But my requirement is the table is already existed with 100000 rows.Now I want to range partition that table.
I’m facing an issue in my current project where we have to run batch jobs and interfaces on the same master tables. These tables are huge (millions) and we get very poor response time.
We thought of partitioning the tables, but the problem is our batch jobs queries are based on dates (some run on monthly data, some runs on yearly data..) but interfaces uses primary keys.
I’m not sure on how to partition the tables in this situation, is there any way I can partition the tables in such a way that both batches and interfaces will get benefit out of it?
Our database infrastructure has a 3 Node RAC (each with 8 CPUs) and oracle 10g R2. We have almost 60gig of RAM allocated to oracle.
PS: We are not thinking about Mviews now because client wants to explore the partition option first.
I have a table where i have ser_id column, this column has got 200000 records and it get around 10 record every day, i want to apply partition on this table.
I am applying range partition of 5000, How can i create partition automatically for next 5000 records inserted into them
I tried to create a backup table as select * from the existing table but still no partition information seems to get transferred. The new table has NO partitions.
