Why is it necessary to precede group by before order by and not vice versa in a sql query? as the foll code gives an error select name from student order by age group by name;
View 3 Repliesii have written a query like thi:
select to_char(order_date,'mon-yyyy') "months", sum(nob) "number of bags"
from p_in where order_date between '1-apr-11 and '31-mar-12'
group by to_char(order_date,'mon-yyyy')
the above query returns me a resultset which gives me number of bags sold in every month, but it does not sort the month in their chronological order. i want to sort my resultset in ascending order of month s.,means jan-feb-march-apr-may ams so on...QUOTE
I have a table name as angdata77 having attributes like asigno..i want to retrieve data from angdata77 by using both group by & order by clauses.. for total count..am using the query as
select asigno,count(*) from angdata77 group by asigno order by asigno;
Is there any other query for retrieving the data from angdata77
Which step in the following plan is the first step of execution
I reckon it is "TABLE ACCESS BY INDEX ROWID| BANK_BATCH_STATE"
Is that correct?
In the "Predicate Information (identified by operation id):"
section the predicates - access and filter for the step "TABLE ACCESS FULL | PYMNT_DUES" are displayed first
Isn't there any relation between the order of execution steps and the order in which predicates are displayed?
Execution Plan
----------------------------------------------------------
Plan hash value: 538700484
-------------------------------------------------------------------------------------------------------------
| Id | Operation | Name | Rows | Bytes | Cost (%CPU)| Time |
-------------------------------------------------------------------------------------------------------------
| 0 | SELECT STATEMENT | | 1 | 2364 | 15 (14)| 00:00:01 |
|* 1 | FILTER | | | | | |
| 2 | HASH GROUP BY | | 1 | 2364 | 15 (14)| 00:00:01 |
| 3 | NESTED LOOPS | | 1 | 2364 | 14 (8)| 00:00:01 |
| 4 | NESTED LOOPS | | 1 | 2313 | 13 (8)| 00:00:01 |
| 5 | NESTED LOOPS | | 1 | 2281 | 12 (9)| 00:00:01 |
| 6 | NESTED LOOPS OUTER | | 1 | 2255 | 11 (10)| 00:00:01 |
|* 7 | HASH JOIN | | 1 | 175 | 6 (17)| 00:00:01 |
|* 8 | INDEX RANGE SCAN | INDX_2 | 12 | 612 | 2 (0)| 00:00:01 |
|* 9 | TABLE ACCESS FULL | PYMNT_DUES | 43 | 5332 | 3 (0)| 00:00:01 |
| 10 | VIEW PUSHED PREDICATE | | 1 | 2080 | 5 (0)| 00:00:01 |
| 11 | NESTED LOOPS | | 1 | 154 | 5 (0)| 00:00:01 |
| 12 | NESTED LOOPS | | 1 | 103 | 4 (0)| 00:00:01 |
|* 13 | TABLE ACCESS BY INDEX ROWID| BANK_BATCH_STATE | 1 | 32 | 2 (0)| 00:00:01 |
|* 14 | INDEX RANGE SCAN | INDX_BBS_1 | 3 | | 1 (0)| 00:00:01 |
|* 15 | TABLE ACCESS BY INDEX ROWID| DAILY_CHECK | 1 | 71 | 2 (0)| 00:00:01 |
|* 16 | INDEX RANGE SCAN | INDX_SEARCH | 1 | | 1 (0)| 00:00:01 |
|* 17 | INDEX RANGE SCAN | INDX_2 | 1 | 51 | 1 (0)| 00:00:01 |
|* 18 | INDEX RANGE SCAN | INDX_IAM_SR_NO | 1 | 26 | 1 (0)| 00:00:01 |
|* 19 | INDEX RANGE SCAN | INDX_2 | 1 | 32 | 1 (0)| 00:00:01 |
|* 20 | INDEX RANGE SCAN | INDX_2 | 1 | 51 | 1 (0)| 00:00:01 |
-----------------------------------------------------------------
I have below tables,
describe rpthead
Name Null Type
--------------------------- -------- -------------
RPTNO NOT NULL NUMBER
RPTDATE NOT NULL DATE
RPTD_BY NOT NULL VARCHAR2(25)
PRODUCT_ID NOT NULL NUMBER
describe rptbody
Name Null Type
------------- -------- -------------
RPTNO NOT NULL NUMBER
LINENO NOT NULL NUMBER
COMMENTS VARCHAR2(240)
UPD_DATE DATE
The fact is that we store some header in RPTHEAD and store real data in RPTBODY, the question is that if I use below SQL to query all data for a 'PRODUCT_ID'.
SELECT t0.LINENO, t0.COMMENTS, t0.RPTNO, t0.UPD_DATE
FROM RPTBODY t0 , RPTHEAD rpthead
WHERE
(
t0.RPTNO = rpthead.RPTNO
AND
t0.UPD_DATE>=to_date('1970/01/01 00:00:00','YYYY/MM/DD hh24:mi:ss')
AND
rpthead.PRODUCT_ID IN ('4647')
)
I do not want to have 'ORDER by' clause since data set is too large, the sorting takes long time, is there any way to get the result rows in the order sorted by RPTNO? We have the index for RPTNO on RPTBODY.
I'm trying to group sets of data based on time separations between records and then count how many records are in each group.
In the example below, I want to return the count for each group of data, so Group 1=5, Group 2=5 and Group 3=5
SELECT AREA_ID AS "AREA ID",
LOC_ID AS "LOCATION ID",
TEST_DATE AS "DATE",
TEST_TIME AS "TIME"
FROM MON_TEST_MASTER
WHERE AREA_ID =89
AND LOC_ID ='3015'
AND TEST_DATE ='10/19/1994';
[code]....
Group 1 = 8:00:22 to 8:41:22
Group 2 = 11:35:47 to 11:35:47
Group 3 = 15:13:46 to 15:13:46
Keep in mind the times will always change, and sometime go over the one hour mark, but no group will have more then a one hour separation between records.
I read that rownum is applied after the selection is made and before "order by". So, in order to get the sum of salaries for all employees in all departments with a row number starting from 1, i wrote :
select ROWNUM,department_id,sum(salary) from employees group by department_id
If i remove rownum, it gives the correct output. Why can't rownum be used here ?
Refer to the txt file to create table and insert data.
I executed the following query-
SELECT priority, detail, COUNT(1) FROM TEST GROUP BY priority, detail
and got the following result-
PRIORITYDETAIL COUNT(1)
StandardPatch 27
StandardInitial TSS 1
StandardInitial development 10
StandardProduction deployment5
High PriorPatch 1
Now I want that Initial TSS and Initial development should be combined as Initial together and I should get the result as follows:
PRIORITYDETAIL COUNT(1)
StandardPatch 27
StandardInitial 11
StandardProduction deployment5
High PriorPatch 1
Is there any way to add one disk group space to another disk group. Because One of my disk group is full i want to add space in to that group.
View 1 Replies View RelatedI'm using this code, and it performs fine, but I'm wondering if there is a more elegant way to do it--maybe with "ROLLBACK". Basically (as you can see) I need to get a normal count for each group but also for each group take a percentage of the total count (so all groups pct adds up to 100 (oh yeah, don't test for zero below, but just a test... )
select
c.Event,
c.code,
count(1) as calls,
total.total_count,
count(1) / total.total_count * 100 as pct_of_total
from
table1 c
[Code]....
[Edit MC: add code tags, do it yourself next time]
Its a very small query
SELECT * from EMPLOY
WHERE fk_dept_id IN ( select id
from DEPARTMENT
ORDER BY END_DT DESC)
I cant use IN.
NOTE: Select * should be done from Employ only no joins and all.
oracle Database 11g Enterprise Edition Release 11.1.0.6.0 - 64bit Production
PL/SQL Release 11.1.0.6.0 - Production
"CORE 11.1.0.6.0 Production"
I have data like:-
event_idiss_nbr
171350 2012051WR
171350 2012041WR
171350 2011081CC
171350 2012041WA
171350 2012031WW
171350 2011081WW
171350 2011081CR
171350 2011081CA
The possible last two characters of the iss_nbr can be:-
WW, WR,WA,CR,CA,CC
And I want it to be ORDER BY as follows.
WR
WA
CR
CA
WW
CC
So for example, in above case, it should be
event_idiss_nbr
171350 2012051WR
171350 2012041WR
171350 2012041WA
171350 2012031WW
171350 2011081CR
171350 2011081CA
171350 2011081WW
171350 2011081CC
How can I do it while loading the table?
I am having table without any primary key. In this table, only inserts and deletes are performed , no update operation.
Is it safe to use order by rowid on such a table ? Does by applying order rowid, is it possible to check order in which rows were inserted in this table ?
In a query which gets executed first:
Select clause or Order by clause? First the columns specified in the select clause are fetched and then ordered or is it the vice -versa? In a query if a psuedo-column rownum is selected, then if we use order by on the rownum column, what happens?
What would be the output of the following query and why?Which part of the query is first executed, is it select clause or order by clause?
select empno,ename,rownum from emp order by rownum desc;
I am having trouble with tab order on a Form.
I rearranged the fields on a form, so I want the tab order to be different. I rearranged the fields in the object navigator to be in the order I want them to tab. I made sure the Previous Navigation Item and Next Navigation Item were set to null for all the fields.
Still it keeps the old tab order.
I also tried explicitly specifying the Previous Navigation Item and Next Navigation Item. Same thing, it kept the old tab order before I rearranged the fields. Previous Navigation Item and Next Navigation Item are both null.
There are no triggers on these fields. All fields are in the same block. I am using Oracle Form Builder version 9.
I have a column named "col1" with datatype "varchar2(10)" and row wise entries like "1,1A, 2,3...,10,2A,..." like. I want to order it like "1, 1A ,2,2A, 2B,3... 10...".I tried it with to_number() but it gives me
1,10,11,2,....like that.
I have requirement to create an XML structure through stored procedure. I need to Order some of the columns in ascending order before I format them into the xml structure. I am pretty novice to creating an output into XML format, but attached is the query I came up with (without order by). This works perfect, but now the requirement is to order by - cls_cd, and within cls_cd, again order by - cat_cd. I am not able to do this.
View 2 Replies View RelatedI am one table create tt1(A varchar2(6),B number(5));
insert data in this column
tt1
A B
---------------
F1 1
F365 2
F10 3
F65 4
F55 5
Q. how to get order by a column. i wan't to
tt1
A
--------------------
F1
F10
F35
F65
F365
Q. how to get order by a column , i wan't to
tt1
A
--------------------
F0001
F0010
F0035
F0065
F0365
create table x(
sno varchar2(5)
);
insert into x values('A-1');
insert into x values('B-1');
insert into x values('B-2');
insert into x values('B-3');
insert into x values('1');
insert into x values('A-2');
insert into x values('2');
insert into x values('3');
insert into x values('A-4');
insert into x values('B-4');
insert into x values('C-4');
insert into x values('D-4');
SQL>select * from x;
SNO
-----
A-1
B-1
1
A-2
2
3
A-4
B-4
C-4
D-4
B-2
B-3
How can I select it ike this
1
A-1
A-2
A-4
B-1
2
B-2
3
B-3
B-4
C-4
D-4
I've got a TRANSACTION table with about 4, 681 transactions going on over the course of a given year (this is a project for my DB class). I'm trying to create a query that will give the base revenue for each month in that year; so far I've come up with the following:
SELECT DISTINCT
CASE
WHEN EXTRACT(MONTH FROM transaction_date) = 1 THEN 'JAN' || ' ' || EXTRACT(YEAR FROM transaction_date)
WHEN EXTRACT(MONTH FROM transaction_date) = 2 THEN 'FEB' || ' ' || EXTRACT(YEAR FROM transaction_date)
WHEN EXTRACT(MONTH FROM transaction_date) = 3 THEN 'MAR' || ' ' || EXTRACT(YEAR FROM transaction_date)
WHEN EXTRACT(MONTH FROM transaction_date) = 4 THEN 'APR' || ' ' || EXTRACT(YEAR FROM transaction_date)
[code]....
The query returns twelve months, but they're all jumbled up. I tried extracting the month in the ORDER BY subclause
ORDER BY EXTRACT(MONTH FROM TO_DATE(month, 'MM YYYY'));
But I got an ORA-01866: the datetime class is invalid. I'm using Oracle 10g xe (outdated, I know). get the months to show up in order?
I have the following sql
select htf.escape_sc(su.sukey) a, htf.escape_sc(su.sukey) b
from udm_su su, udm_lde lde
where su.ldeid = lde.ldeid
and su.sukey in (select su_generic
[code]...
I am using 11GR2 and looking to find out a way , where in I able to extract the data files name in such a manner , where it lists data file in order of mount points. say data1 first and then so on.. Snippet from my data files
output. /db/ptmtrain/data1/system01.dbf/db/ptmtrain/data2/sysaux01.dbf/db/ptmtrain/data1/undotbs01.dbf/db/ptmtrain/data3/tools01.dbf/db/ptmtrain/data24/users01.dbf/db/ptmtrain/data25/users02.dbf/db/ptmtrain/data26/users03.dbf/db/ptmtrain/data2/rbs01.dbf/db/ptmtrain/data3/rbs02.dbf/db/ptmtrain/data2/rbs03.dbf/db/ptmtrain/data23/sans01.dbf
should be something
like /db/ptmtrain/data1/system01.dbf/db/ptmtrain/data1/undotbs01.dbf/db/ptmtrain/data2/sysaux01.dbf/db/ptmtrain/data2/rbs03.dbf/db/ptmtrain/data2/rbs01.dbf/db/ptmtrain/data3/tools01.dbf/db/ptmtrain/data3/rbs02.dbf/db/ptmtrain/data23/sans01.dbf/db/ptmtrain/data24/users01.dbf/db/ptmtrain/data25/users02.dbf/db/ptmtrain/data26/users03.dbf
create table members(
memberID varchar2(7),
locationID number(5),
roomID varchar2(5)
)
/
[Code]....
MEMBERI LOCATIONID ROOMI
------- ---------- -----
2007209 1 1
2006253 1 1-A
2006253 1 1-A
2006265 1 1-B
2006240 1 1-C
2005064 1 1-D
2007836 1 100
2007211 1 101
2007075 1 102
2007110 1 105
[Code]...
Function created.
SQL> select * from members
2 order by safe_to_number(roomID);
MEMBERI LOCATIONID ROOMI
------- ---------- -----
2007209 1 1
2007185 1 2
2007089 1 3
2007023 1 4
[Code]....
How can I sort the output to get the result like below
2007209 1 1
2006253 1 1-A
2006253 1 1-A
[Code]...
and so on...
How I can see the order by employees,year wise and monthwise (month should start from january and so on..)
SELECT ENAME,TO_CHAR(HIREDATE,'yyyy') YEAR,TO_CHAR(HIREDATE,'Month') MONTH ,count(*) total
FROM EMP
GROUP BY TO_CHAR(HIREDATE,'yyyy') ,TO_CHAR(HIREDATE,'Month');
I have a varchar2 column which can hold numeric values, and also varchar2 values.
The following select returns only the records which have a number value in that column
select * from my_table
order by decode(
replace(translate(valoare,'1234567890.','00000000000'),'0',''), NULL,
valoare, 0 ) != 0;
But how can i order that column, so that first are the numbers (also ordered), and then the varchar2 columns (so all the rows of that table are selected, both varchar2 values and numbers in that column)? Is it possible?
I have a requirement where I need to display a list of employees, performance rating and manager id. I want to display the employees first whose manager is as manager_id as input parameter. So lets say a manager logs in, he should see his reporters first and then the rest. How can I implement this in SQL? I am trying first clause with order by but not sure how to do that here.
procedure
display_list(manager_id in varchar2)
Output is:
emp_id
manager_id
performance_rating
I have a table (emp) with three columns in ORACLE:
COMPANY OFFICE EMP
------------------------
9999 00001 emp1
9999 00001 emp2
9999 00002 emp3
9999 00002 emp4
[code]...
I want to get value in EMP column with following statement:
-------------
SELECT
EMP
FROM
emp
ORDER BY COMPANY (But 9999 is first), OFFICE (But 99999 is first).
-------------
I don't know how to do.
I have a query with order by clause, which takes 30 sec to execute with order by clause. And if i remove the order by clause it executes within 1 sec.
The column in the order by condition has index. but when i see Explain plan output. it doesn't show this index is being used. I tried to execute query with INDEX hint but still explain plan is not showing this index.
In sql server we can able to change the order of a column but some says in oracle also we can do it. But as i think it is not possible.
View 3 Replies View Relatedi have a table test on 4 different-different database, at the starting structure is same in all the database. and now i want to change the datatype of the primary key column named "testid" , then i add a temp column in test table (and it is added at the last in table).
i have copied the data of testid in temp column and renamed it as testid and i dropped the testid column , then the problem is that primary key column will comes at last and i want to make it like previous position so that there will not be any difference in all 4 database as in structure.
is it possible to changing column order as our desire without dropping the table?and i made all the script to changing the datatype of primary key column.