I got a error while creating a partition table
I did following steps
SQL> show user
USER is "ROSE"
SQL>
SQL> create table sales (year number(4),
2 product varchar2(10),amt number(10,2))
3 partition by range (year)
[code]....
ORA-00922: missing or invalid option
SQL>
SQL> SELECT NAME FROM V$TABLESPACE;
NAME
------------------------------
SYSTEM
UNDOTBS1
SYSAUX
USERS
[code]....
I am getting error while trying to create a table
SQL>
SQL> CREATE OR REPLACE TABLE CEE_OSPCM_DETAILS
2 (
3 ORD_NBR VARCHAR2(10) NOT NULL,
4 ORD_APPNDX NUMBER(2) NOT NULL,
5 FRCOI_NBR NUMBER,
6 PRINT_NBR VARCHAR2(4),
[code]....
create or replace p_aggop(dno number, maxi number,mini number,avgi number,tot number,cnt number) is
cursor c1 is select * from emp1 WHERE DEPTNO=dno GROUP BY DEPTNO;
v_emp1 c1%rowtype;
begin
open c1;
loop
fetch c1 into v_emp1;
select min(v_emp1.sal),max(v_emp1.sal),avg(v_emp1.sal),sum(v_emp1.sal),count(*) into mini,maxi,avgi,tot,cnt from v_emp1;
exit when c1%notfound;
Dbms_output.put_line('EXECUTED ');
end loop;
dbms_output.put_line('The minimum salaray in dept is :'||v_emp1.mini);
dbms_output.put_line('The maximum salaray in dept is :'||v_emp1.maxi);
dbms_output.put_line('The average salaray in dept is :'||v_emp1.avgi);
dbms_output.put_line('The total salaray in dept is :'||v_emp1.tot);
dbms_output.put_line('The total members in dept is :'||v_emp1.cnt);
CLOSE C1;
end;
I am creating a stored procedure to create a table during run time using 3 passed in parameters to build the table name. Oracle is giving me the ORA-00922 missing or invalid operation error message on the EXECUTE IMMEDIATE statement of my stored procedure. I am new to writing stored procedures in Oracle. I am pasting a copy of the stored procedures. I have also changed the names of the field names to be generic so I can post the code in this forum.
CREATE OR REPLACE PROCEDURE createTable(PARAMETER1 in string, PARAMETER2 in string, PARAMETER3 in string) IS
TABLE_NAME NVARCHAR2(50);
QUERY_STRING LONG;
BEGIN
[Code]....
i have managed to put in 2 link tables but I cannot seem to manage the last.
I am getting the error:
ORA-00922: missing or invalid option
----LINK TABLE----
Code Used:
CREATE TABLE cs-lt
(
ID VARCHAR(4),
CASE_ID VARCHAR(4),
SOLICITOR_ID VARCHAR(4),
FOREIGN KEY ( case_id ) REFERENCES case(case_id), FOREIGN KEY ( solicitor_id ) REFERENCES SOLICITOR(SOLICITOR_ID), PRIMARY KEY ( CASE_ID, SOLICITOR_ID )
);
And the code for the other relating tables:
------CASE TABLE----------
CREATE TABLE "CASE"
( "CASE_ID" VARCHAR2(4),
"CASE_NAME" VARCHAR2(30),
"CASE_START_DATE" NUMBER(12,0),
"CASE_DESC" VARCHAR2(50),
"CONTRACT_ID" VARCHAR2(3),
"SOLICITOR_ID" VARCHAR2(4),
[code]....
I ran the following PL/SQL Code & I am getting the following Error:
Drop table MODIFIEDTABLE
/
Commit
/
create table MODIFIEDTABLE(TABNAMES varchar2(100))
/
DECLARE
[code].....
RESULT:
Table dropped.
Commit complete.
Table created.
DECLARE
*
ERROR at line 1:
ORA-01735: invalid ALTER TABLE option
ORA-06512: at line 12
I am trying to create two tables and I am getting the "ORA-00911: invalid character" Error. I have been trying to work it out for last past 30 minutes to no success.
CREATE TABLE special_rate
(
rate_id VARCHAR(3),
rate VARCHAR(5),
rate_expiry_date NUMBER(12),
PRIMARY KEY( rate_id ),
FOREIGN KEY( contract_id ) REFERENCES contract(contract_id)
[code]....
I am using 11.2.0.2 database.
I got ORA-14074 error says that if you have a MAXVALUE already you will need to either drop the partition that encompasses the MAXVALUE or split partition.So I want to use split partition option through the below statement,
alter table
tablename
split partition
partmax at (XXX)
into
(partition partXXX, partition partmax);
I am concerned about the existing data in the table will it by any change gets deleted, and what about indexes, do I have to rebuild, etc.I have to do this on produciton. I cannot test this as I don't have a test environment and moreover the table is having 70 million records and we don't have time/hardware resources to recreate this by export import in another database.
I want to purge scott's recycle bin as user "SYSTEM". Because I do not know the user's password. How do I achieve it?
SQL> purge scott.recycle bin;
purge scott.recycle bin
*
ERROR at line 1:
ORA-38302: invalid PURGE option
I got this error when try to connect to the database using discover administrator or user edition
ora - 02248 : invalid option for ALTER SESSION
i can connect to the database with sqlplus with no problem.
creating Oracle SQL query to fetch the information using PIVOT option.We are populating audit table using triggers. For every update, there will be two rows into audit table, one row with all OLD values and another with all NEW values. Also every updated is uniquely identified by Sequence No. Example for phone audit is mentioned below :
CREATE TABLE test_audit_phone
(
emplid VARCHAR2(10),
seqno NUMBER,
action VARCHAR2(3),
office NUMBER,
mobile NUMBER
);
Insert some rows into table.
INSERT INTO test_audit_phone VALUES ('100',1,'OLD',1111,9999)
/
INSERT INTO test_audit_phone VALUES ('100',1,'NEW',2222,9999)
/
INSERT INTO test_audit_phone VALUES ('100',2,'OLD',2222,9999)
/
INSERT INTO test_audit_phone VALUES ('100',2,'NEW',2222,8888)
/
Table will look like the following :
SQL> SELECT * FROM sysadm.test_audit_phone ;
EMPLID SEQNO ACT OFFICE MOBILE
---------- ---------- --- ---------- ----------
100 1 OLD 1111 9999
100 1 NEW 2222 9999
100 2 OLD 2222 9999
100 2 NEW 2222 8888
Now we have to present data in different format. For each field, display OLD and NEW values in column format.
EMPLIDFIELDOLDNEW
----- ------ ---- -----
100OFFICE11112222
100MOBILE99998888
Challenges :
1) Make pivoting with old and new values
2) For each field we have to show old and new values
3)if old and new values are same, dont show in report.
I wrote a function:
create or replace function get_search_condition(p_cons_name in varchar2 ) return varchar2 authid current_user is
l_search_condition user_constraints.search_condition%type;
begin
select search_condition into l_search_condition
from user_constraints
where constraint_name = p_cons_name;
return l_search_condition;
end;
and ran it...then when I write the below command:
alter table employee drop constraint
select constraint_name from user_constraints where table_name = 'EMPLOYEE' and
get_search_condition(constraint_name) like '%(( ROLL_NUMBER > 0 ))%'
;
The system throws:
Error starting at line 1 in command:
alter table FL_ITEMSITE drop constraint
select constraint_name from user_constraints where table_name = 'FL_ITEMSITE' and
get_search_condition(constraint_name) like '%(( SS_QTY > 0 ))%'
Error report:
SQL Error: ORA-02250: missing or invalid constraint name
02250. 00000 - "missing or invalid constraint name"
*Cause: The constraint name is missing or invalid.
*Action: Specify a valid identifier name for the constraint name.
i want to drop constraint without specifying its name. i want the system to fetch it dynamically.
I have this requirement to pull the ACTIVE days that a participant holds true in a given month for a specific position he/she holds.The three date ranges here are: LOA dates(leave of absence), XFER dates(TRANSFER in/out of the position),Quality compliance(QUAL start/end dates).So,
INACTIVE DAYS = [(LOA + XFER + WW) - OVERLAPPING DAYS OF (LOA+XFER+QUAL)]
CREATE TABLE PAYEES
(
RUN_PERIOD DATE NOT NULL,
PAYEEID VARCHAR2(20 BYTE) NOT NULL,
LOA_START_DATE DATE,
LOA_END_DATE DATE,
[code]....
I am able to pull out the no of days on a individual basis(count of days for Xfer/LOA/Qual) but I am really not sure as to how should i go about determining the overlapping days between 3 date ranges to determine the ACTIVE/INactive days.
I think that performance better partition table than non-partition table. How to assure partition table is better than non-partition table at SELECT operation?
I have compare a specific query EXPLAIN PLAN at partition table and non-partition table. both tables data is same. Is it true way or not?
i want to create tablespace in raw partion on windows.I have added a hard disk and added extended partition to it. Then created 4 logical partitions of 256 MB with diskpart.exe.I have assigned a drive letter to one of them as X:
However, I am having trouble in creating tablespace on it. I referred to [URL]... I get following error,
C:UsersAdministrator>sqlplus
SQL*Plus: Release 11.2.0.1.0 Production on Fri Aug 17 15:32:17 2012
Copyright (c) 1982, 2010, Oracle. All rights reserved.
Enter user-name: SYSTEM
Enter password:
Connected to:
Oracle Database 11g Enterprise Edition Release 11.2.0.1.0 - Production
With the Partitioning, OLAP, Data Mining and Real Application Testing opti
SQL> create tablespace exampletb datafile '\.X:accounting_1' size 100;
create tablespace exampletb datafile '\.X:accounting_1' size 100
ERROR at line 1:
ORA-03214: File Size specified is smaller than minimum required
SQL> create tablespace exampletb datafile '\.X:accounting_1' size 502;
create tablespace exampletb datafile '\.X:accounting_1' size 502
[code]...
I have a table that partitioned into six partitions. each partitions placed in different table space and every two table space placed it on a different hardisk
when I will do query select with the non-partition keys condition, how the search process ? whether the sequence (scan sequentially from partition 1 to partition 6) or partition in a hardisk is accessed at the same time with other partition in other hardisk. ( in the image, partition 1,4 accessed at the same time with partition 2,5 and 3,6)
Can i alter the table to create partition on non partition table, i have tried and could not create it. Do we have some other means to do it as this is the live table and cannot drop them else will lose the data.
View 1 Replies View RelatedCan I add range sub partition to a hash partition table. Example like this.
CREATE TABLE test
(
test_id VARCHAR2(10 ) ,
test_TYPE VARCHAR2(5) ,
CREATE_DATE date
)
partition by hash (test_id, test_type)
Partitions 3
SUBPARTITION BY RANGE (CREATE_DATE);
When Tried, I am getting syntax error as invalid option.
i want to create a new partition for version 2
existing table is as below
create table test
(
name varchar2(100),
version NUMBER(12)
)
[Code]....
I have two tables in which one is partitioned table with the following details.
CREATE TABLE "SCOTT"."TBL_MITTAL"
("ACCOUNT_NAME" VARCHAR2(50 BYTE),
"BILL_NO" VARCHAR2(50 BYTE),
"BILL_DATE" VARCHAR2(50 BYTE),
"CLI" VARCHAR2(50 BYTE),
"ANI" VARCHAR2(50 BYTE),
[code].....
When I am trying to insert record from tbl_mittal into tbl_temp table. I am facing "ORA-14400: inserted partition key does not map to any partition" error
SQL> insert into tbl_temp select * from tbl_mittal;
insert into tbl_temp select * from tbl_mittal
*
ERROR at line 1:
ORA-14400: inserted partition key does not map to any partition
AS tbl_mittal is having hugh number of records so I am providing only few rows from tbl_mittal table as test data.
ACCOUNT_NAMEBILL_NOBILL_DATECLIANICHARGE_START_DATEDURFROM_LOCATIONTO_LOCATIONINVOICE_IDCIRCLE
10000010357423128271095119301-Feb-111723006000931488182328-JAN-11 11.30.54.000000000 AM59.04CHANDIGARHJAIPUR271095119
10000011844187128348720198715-Jun-121409470011825531896615-MAY-12 09.10.36.000000000 AM28.03CHANDIGARHBANTWAL348720198
10000011844187128348720198715-Jun-121409470011825531927115-MAY-12 09.10.41.000000000 AM38.32CHANDIGARHBANTWAL348720198
10000011844187128348720198715-Jun-121409470011825531933015-MAY-12 09.10.46.000000000 AM28.81CHANDIGARHBANTWAL348720198
10000011844187128348720198715-Jun-121409470011825531930215-MAY-12 09.10.53.000000000 AM28.96CHANDIGARHBANTWAL348720198
[code].....
I also tried to upload the same data using sqlldr.
sqlldr log file contents is as follows:
Total logical records skipped: 0
Total logical records read: 1857532
Total logical records rejected: 801092
Total logical records discarded: 37
[code].....
So some sqlldr bad file contents is as follows.
100000118441871,283487201987,15-JUN-12,1723958000,9355115251,10-JUN-12 05.56.05.000000 PM,36.99,CHANDIGARH,AMBALA,348720198,,
100000118441871,283487201987,15-JUN-12,1723958000,7520533825,10-JUN-12 05.56.14.000000 PM,44.12,CHANDIGARH,AGRA,348720198,,
100000118441871,283487201987,15-JUN-12,1723958000,9356452151,10-JUN-12 05.56.17.000000 PM,116.83,CHANDIGARH,JALANDHAR,348720198,,
100000118441871,283487201987,15-JUN-12,1723958000,9331223048,10-JUN-12 05.56.21.000000 PM,28.33,CHANDIGARH,KOLKATA,348720198,,
100000118441871,283487201987,15-JUN-12,1723958000,7827927893,10-JUN-12 05.56.24.000000 PM,3384.33,CHANDIGARH,DELHI,348720198,,
[code].....
How to find the size pf a partition in a partition table?I guess we need to query views like dba_tab_partitions but I am not very sure. will running dbms_stats.gather_table_stats('schema_name,'table_name,'partition_name')
View 3 Replies View RelatedWhat is the Best option for SQL/sybase server Temp table to use/for data manipulation (Insert/update/delete) inside the procedure in oracle Other then global temporary table.
Since we are porting from SQL/Sybase to Oracle we don't want to Create too many global temporary table.
I am trying out the COMPRESS option along with CREATE TABLE. just wanted to understand if we need the "Advanced Compression" option enabled. Does this require extra license?
View 2 Replies View RelatedI think that performance better partition table than non-partition table. How to assure partition table is better than non-partition table at SELECT operation?
I have compare a specific query EXPLAIN PLAN at partition table and non-partition table. both tables data is same. Is it true way or not?
l am loading data i.e text file of huge size into oracle 9i db using sqlldr through command prompt, but my table contains already some data so while loading it shows error as
SQL*Loader-601: For INSERT option, table must be empty.
i cant truncate my table since present data is important.
In my database I found some anomalies like
SQL> select SEGMENT_NAME, SEGMENT_TYPE, BLOCKS, EXTENTS, BYTES/1024
2 from user_segments
3 where SEGMENT_TYPE='TABLE'
4 ORDER BY SEGMENT_NAMe;
[code]....
The countries table is missing in user_segments data dictionary view.But I can queries the countries using select statement.
SQL> SELECT * FROM COUNTRIES;
CO COUNTRY_NAME REGION_ID
-- ---------------------------------------- ----------
AR Argentina 2
AU Australia 3
BE Belgium 1
BR Brazil 2
[code]...
why the country table is missing in user_segments data dictionary table.
I am trying to add partition to table without partition
with following code
ALTER TABLE ACC_LOC1_TAB
ADD PARTITION testpart BY RANGE (ALT_AUTHDT)
(PARTITION UPTO_2010 values less than (31-mar-2010),
PARTITION APR_JUN_10 VALUES less than (30-JUN-2010),
PARTITION JUL_SEP_10 VALUES less than (30-SEP-2010),
PARTITION OCT_DEC_10 VALUES less than (31-DEC-2010),
PARTITION JAN_MAR_11 VALUES less than (31-MAR-2011))
it will raise error ora-14020
I am using Oracle 11.2.0.1 Oracle Database.I have a table with 10 Million records and it's a Non Partitioned Table.
1) I would like to partition the table (with partition by range ) without creating new table . I should do it in the existing table itself (not sure DBMS_ REDEFINITION is the only option ) (or) can i use alter table ...?
2) Add one partition which will have data for the unspecified range.
i have table with range partition and list sub-partition..can i add one more list sub-partition if it is not possible , i have to drop first sub-partition.
View 6 Replies View RelatedSELECT c.table_name CHILD_TABLE, p.table_name PARENT_TABLE
FROM user_constraints p, user_constraints c
WHERE (p.constraint_type = 'P' OR p.constraint_type = 'U')
AND c.constraint_type = 'R'
AND p.constraint_name = c.r_constraint_name
AND c.table_name = UPPER('ODS_TSAF_MES_PC');
and output is
child table parent table
ODS_TSAF_MES_PC ODS_TSAF_MES_PCTYP
ODS_TSAF_MES_PC ODS_TSAF_MES_PC
ODS_TSAF_MES_PC ODS_TSAF_MES_PCSTAT
i tried
SELECT A.piecestatus from ods_TSAF_MES_PCSTAT A WHERE NOT EXISTS
(SELECT * FROM ODS_TSAF_MES_PC B WHERE B.piecestatus = A.piecestatus);
and i found one piecestatus values is 'I' but i am not getting where it is related to the table and in which row it is getting affected?