I get data from one table into a gridview and one of the columns is a date. I get it with date and time stamp but I want solely the date in my gridview.
This is what I get: 2009-08-04 00:00:00
This is what I want: 2009-08-04
I am wanting to write a procedure which takes in a TIMESTAMP datatype as a parameter. I only really want the time, not the date part.I am struggling to understand however what format the inserted TIMESTAMP would take. E.g
function_name( 'timestamp')
--would this be;
function_name('12:00');
--or something along those lines?
I am trying to insert values in the timestamp field
system@id.world> create table t(t1 timestamp,t2 timestamp, t3 timestamp, t4 date);
Table created.
system@id.world> insert into t values(timestamp'2011-03-24 11:03:00.05','12-mar-2011 11.03.00.055',systimestamp,localtimestamp);
1 row created.
system@id.world> insert into t values(timestamp'2011-03-24 14:03:00.05','12-mar-2011 14.03.00.055',systimestamp,localtimestamp);
1 row created.
system@id.world> select t1 from t;
T1
---------------------------------------------------------------------------
24-MAR-11 11.03.00.050000
24-MAR-11 14.03.00.050000
system@id.world> select t2 from t;
T2
---------------------------------------------------------------------------
12-MAR-11 11.03.00.055000
12-MAR-11 14.03.00.055000
system@id.world> select t3 from t;
T3
---------------------------------------------------------------------------
24-MAR-11 11.29.04.491927
24-MAR-11 11.29.17.085396
system@id.world> select t4 from t;
T4
---------
24-MAR-11
24-MAR-11
system@id.world> select * from nls_instance_parameters;
PARAMETER VALUE
------------------------------ ----------------------------------------
NLS_LANGUAGE AMERICAN
NLS_TERRITORY AMERICA
NLS_SORT
NLS_DATE_LANGUAGE
[Code]...
PARAMETER VALUE
------------------------------ ----------------------------------------
NLS_TIME_TZ_FORMAT
NLS_TIMESTAMP_TZ_FORMAT
NLS_DUAL_CURRENCY
NLS_COMP
NLS_LENGTH_SEMANTICS BYTE
NLS_NCHAR_CONV_EXCP FALSE
17 rows selected.
system@id.world> select * from nls_database_parameters;
PARAMETER VALUE
------------------------------ ----------------------------------------
NLS_LANGUAGE AMERICAN
NLS_NCHAR_CHARACTERSET AL16UTF16
NLS_TERRITORY AMERICA
NLS_CURRENCY $
[Code]...
PARAMETER VALUE
------------------------------ ----------------------------------------
NLS_TIME_FORMAT HH.MI.SSXFF AM
NLS_TIMESTAMP_FORMAT DD-MON-RR HH.MI.SSXFF AM
NLS_TIME_TZ_FORMAT HH.MI.SSXFF AM TZR
[Code]...
20 rows selected.
system@id.world> show parameter nls_timestamp_fo
NAME TYPE VALUE
------------------------------------ ----------- ------------------------------
nls_timestamp_format string
system@id.world> create table newt(t1 timestamp);
Table created.
system@id.world> select localtimestamp from dual;
LOCALTIMESTAMP
---------------------------------------------------------------------------
24-MAR-11 11.31.07.667296
system@id.world> insert into newt values('12-jan-2010 11:00:00:068801');
insert into newt values('12-jan-2010 11:00:00:068801')
*
ERROR at line 1:
ORA-01830: date format picture ends before converting entire input string
system@id.world> insert into newt values('12-jan-2010 11.00.00.061');
1 row created.
system@id.world> insert into newt values('12-jan-2010 15.00.00.061');
1 row created.
system@id.world> select * from newt;
T1
---------------------------------------------------------------------------
12-JAN-10 11.00.00.061000
12-JAN-10 15.00.00.061000
system@id.world>
My questions are
1) what is significance of '.' here? insert into t values(timestamp'2011-03-24 11:03:00.05','12-mar-2011 11.03.00.055',systimestamp,localtimestamp);
2) while inserting using "values(timestamp'2011-03-24 11:03:00.05'" where this yyyy-mm-dd hh24:mi:ss.FF format comes from?
3)what is role of nls_timestamp_format of nls_database_parameters in this? how it allowed me to insert value "'12-mar-2011 14.03.00.055'" which has hh24 format?
4) Does the format of localtimestamp is decided by nls_database_parameters?
Note : I have not set nls_date_format in my session
I tried to read the link below but could not understand above
[URL]....
From ETL to Oracle, I have stored the timestamp in varchar2 as '30-MAY-11 06.30.00.000000 PM'. Now I need to convert this varchar2(timestamp format) to date. I used:
select TRUNC('30-MAY-11 06.30.00.000000 PM','dd/mm/yyyy hh24:mi') from dualBut, it doest work. get date format?
How to extract date from a timestamp data
for example
Input-15/06/2010 05:30:00.000000
output: 15/06/2010
how to convert date into UNIX time in oracle ?
View 1 Replies View RelatedI want to write a query to get the time stamp from only one date column,
I tried using a group by clause but getting error "not a group by exp."
Below is the query
SELECT ProdID,ProdRequestID, SUBSTR((max(EVENTTIMESTAMP) - min(EVENTTIMESTAMP)), 18,2)Execution_Time
FROM LOG_TIMESTAMPS where ProdID = 1680988889
group by ProdRequestID
ProdID||ProdRequestID ||EVENTTIMESTAMP
[code]....
In the above i am looking for a diference on ProdRequestId,
Output
ProdIDProdRequestIDEVENTTIMESTAMP
16809888892013-04-09T02-56-34.5025kqcxy03
How can i get just date from the timestamp data type.
Suppose i have a column timestamp with has data like "2011-05-16 16:19:22.579764-07" when i select from table i just want the date like 2011-05-16.
I have a timestamp field in an oracle table. The data in that field looks like this.
19-MAY-2011 10.55.21.628206000 AM
I want to query the data in this field by only date portion (not the time portion).
Something like this.
Select * from mytable where archivedate = to_date('19-may-2011','dd-mon-yyyy')
this query doesn't return any data. But actually there is data for 19-may-2011 (along with time portion) in that field.
how to query based on only date portion?
how to extract DATE from timestamp column
View 2 Replies View RelatedWhen I run a query form the the Query Window in Visuial Studios 2012 all the date fields truncated to 'mm/dd/yyyy', but i need the full date returned. I am able to get full date from TO_char(MyDateField, 'yyyy-mm-dd hh24:mi:ss'), but if I do TO_DATE(MyDateField, 'yyyy-mm-dd hh24:mi:ss') it only returns 'mm/dd/yyyy'. I'm sure this is a simple setting in Visual studios but I cant find it to save my life. Is there there a way to have the full date returned by default?
View 0 Replies View RelatedHow can i separate the Date and time into two separate fields from the Oracle TIMESTAMP?
View 1 Replies View RelatedI want to retrieve the data which is "n" moths old.
To compare that I want use only SYSDATE without timestamp. I want to use standard timestamp '23:59:59' along with SYSDATE.
The condition should be as below.
UPDATE_DATE <= ADD_MONTHS(15/01/2013 23:59:59,-3)
UPDATE_DATE <= ADD_MOTHS(30/01/2013 23:59:59,-4)
UPDATE_DATE<=ADD_MONTHS(sysdate||' '||'23:59:59',-3);
A field named xxx_date is a text item which we have to enter manually so as to update a record in that particular date. This is a mandatory field without which we cannot continue the data entry..
I am getting this error while trying to update the record
FRM-40509 :Oracle error :unable to update record
I have kept the enabled = yes
required=no
data type=Date.. in the property pallet
I want to reset my date to this format: 12/31/2012 11:59:59 PM - see code below:
DECLARE
v_latest_close DATE;
BEGIN
v_latest_close := TO_DATE ('12/31/2012 23:59:59 ','MM/DD/YYYY HH24:MI:SS');
DBMS_OUTPUT.PUT_LINE('The new date format is : '|| v_latest_close);
END;
the code above displays only : 12/31/2012 instead of 12/31/2012 11:59:59 PM
Due to some business requirements a table field needs to change from date to timestamp in order to handle the millisecs.
1>When i alter the row , for a table with 150 million recs will there be a conversion. Is there a recommended way to convert the field. Mind you this field is used as a part of composite PK.
2> There is a interfacing application which connects and copies the data to its system and is using the date type, will that application be able to continue to work without any changes, if it does not care about the millisecs.
3> Will there be performance impact on an existing application that uses the date field to sort
4> Will DB need more space due to the change
I am using apex 4.2, mod_plsql
the url of application is very long, is there any way to make it short
I have a column where I have time stamp with date and time(8-May-10 10:20:55 Am) from that i will get only time(10:20:55 Am)[query for this mentioned below] Now i need to append the time to current date and insert into a Timestamps column only .
so my result should be 17-May-11 10:20:55 Am(Assuming current Date is 17-May-11) . I tried search it by i found a way in sql server by using DataAdd and DataDiff .
query to get the time is:select to_char(to_date('11-MAY-11 05.00.00 PM', 'DD-Mon-YY HH:MI:SSAM'),'HH24:MI:SS') "Time Now" from dual
I have table named purchage with 2 columns (order_no number,order_date date) in my database. I want to load the data from a file into that table. The below is the file format
100,4/3/2013 1:18:18 AM
101,4/3/2013 1:18:18 AM
102,4/3/2013 1:18:18 AM
103,4/3/2013 1:18:18 AM
104,4/3/2013 1:18:18 AM
105,4/3/2013 1:18:18 AM
106,4/3/2013 1:18:18 AM
how to load the date filed along with the time stamp.
In one of the query used like below is it correct or any need to be correct for date format? currently it's returning two tyoe of sets 1.NUll 2.01-JAN-00
SELECT withdrawn_date
FROM
csd where NVL(csd.withdrawn_date,'01-JAN-1900') = '01-JAN-1900';
How do I format a date which is this format to 2/18/2012 to 18/2/2012 and still keep the field as Date.
View 3 Replies View RelatedWhat is the difference between the following . In my schema all are giving the same results with some different format
SQL> SELECT sysdate , current_date , current_timestamp , localtimestamp from dual;
SYSDATE CURRENT_DATE CURRENT_TIMESTAMP LOCALTIMESTAMP
----------- ------------ ------------------------------------------------- -------------------------------------------------
5/30/2012 8 5/30/2012 8: 30-MAY-12 08.27.22.037703 AM -04:00 30-MAY-12 08.27.22.037703 AM
i see my dates in Oracle 11g like this: 2012-December-30 (in all my tables)
how to configure Oracle that i can see it like this: 30/12/2012
I have a simple question, hope it has a simple answer. I changed the default date format for a SCHEMA using a TRIGGER and AFTER LOGON, so it set the NLS_DATE_FORMAT='YYYY-MM-DD HH24:MI:SS'. It does work fine, however, the problem is when I connect using a client with JDBC driver. When using SQL PLUS I get the date in the format specified above YYYY-MM-DD HH24:MI:SS, however, when using a client (Aqua Data 6.5.8 I know it is kinda old) and SQuirrel SQL 3.4.0 I always get the date in the YYYY-MM-DD format. I started to think that the issue is with the JDBC because it works fine when I connect with SQLPLUS.
View 5 Replies View RelatedHow can I check if date is in correct format ? I have In parameter for function. It is date. Example:
2011-11-01
How can I check this format ?
iam having a table A where column ABC is a varchar field with varchar2(50).
currently data stored is like this.
02-27-2009 11:01:33
02-27-2009 11:01:46
03-06-2009 09:07:18
now i want UTC Date time should be in format 2010-02-24T17:08:09Z. in the above format.
I want to change the date format at database level in 10g express edition.
When i try to run the command,
ALTER SYSTEM SET NLS_DATE_FORMAT='DD/MM/YYYY',
it throws error like specified initialisation parametr is not modifiabale with this option.
what are the other ways to chnage the database date format to the desired one.?
follwing is my structure and data in table. COLA has datatype varchar2.data in table is date..... now i want to convert all the dates in 'yyyymmdd' format.
IS it possible?
SQL> select * from taba;
COLA
---------------
1944-02-10
1982-07-20
08/24/1974
03/14/1957
22-Nov-79
While am working with Decode just found something, why it is returning like this.
I Ran this query where i have used all the date format as DD/MM/YYYY
SELECT DECODE(TO_DATE('25/04/2001','DD/MM/YYYY') ,
TO_DATE('01/01/1900','DD/MM/YYYY'), NULL ,
TO_DATE('25/04/2001','DD/MM/YYYY')) TEST
FROM DUAL
Quote:
TEST
-------------
25-APR-01
But the resule i got in DD-MON-YY
i tried searching this forum with searching strings Decode date format.. or similer i found nothing.
I have below data
SQL> desc IMEI
Name Null? Type
----------------------------------------- -------- ----------------------------
MSISDN NOT NULL VARCHAR2(20)
IMEI NOT NULL VARCHAR2(16)
DATE_MOD NUMBER(13)
IMSI VARCHAR2(18)
ICCID VARCHAR2(20)
T_PROF RAW(20)
EXTRA_DATA VARCHAR2(100)
SQL> select DATE_MOD from IMEI;
DATE_MOD
----------
1.2199E+12
1.2348E+12
1.2278E+12
1.2263E+12
1.2278E+12
1.2378E+12
1.2414E+12
How can I change date_mod to normal date format like year/month/day hour:minutes:second ?
